2(8+p)=22
these two questions are confusing to me can someone explain them please!
5(a-1)=35
2(8+p)=22
16 + 2p = 22
2p = 6
p = ?
That's the first one. You can do the second one -- and we'll be glad to check your answer.
excuse me but i was wondering how you got 2p=6
2(8+p)=22
First do the multiplication:
2 * 8 = 16
2 * p = 2p
Then subtract 16 from both sides of the equation.
16 - 16 + 2p = 22 - 16
2p = 6
thank you so much i understand now
Great!
Certainly! Let's go step by step to solve each equation.
1) 2(8+p)=22
To solve this equation, we need to follow the order of operations, also known as PEMDAS (Parentheses, Exponents, Multiplication/Division, Addition/Subtraction).
First, we can simplify the left side of the equation by distributing 2 to both terms inside the parentheses:
2 * 8 + 2 * p = 22
Now we can simplify further:
16 + 2p = 22
Next, we want to isolate the variable on one side of the equation. In this case, we want to get rid of the 16 on the left side to have just the "2p" term. Since 16 is being added to the left side, we can subtract 16 from both sides of the equation to maintain equality:
16 - 16 + 2p = 22 - 16
This simplifies to:
2p = 6
Finally, to solve for the variable "p", we divide both sides of the equation by 2:
2p/2 = 6/2
The equation becomes:
p = 3
So the solution to the equation 2(8+p)=22 is p = 3.
2) 5(a-1)=35
Similarly, we follow the order of operations to solve this equation.
First, we can distribute 5 to both terms inside the parentheses:
5 * a - 5 * 1 = 35
This simplifies to:
5a - 5 = 35
Next, we want to isolate the variable on one side of the equation. In this case, we want to get rid of the -5 on the left side. Since -5 is being subtracted from the left side, we can add 5 to both sides of the equation to maintain equality:
5a - 5 + 5 = 35 + 5
This simplifies to:
5a = 40
Finally, to solve for the variable "a", we divide both sides of the equation by 5:
5a/5 = 40/5
The equation becomes:
a = 8
So the solution to the equation 5(a-1)=35 is a = 8.
I hope this explanation helps! Let me know if you have any other questions.