how many kilojoules of energy are required to bring 800.0g water from 20.0c to the boiling point.
not sure what formula is? 4.184j
q = mass H2O x specific heat H2O x (Tfinal-Tinitial)
To calculate the amount of energy required to heat a substance, you can use the formula:
Q = mass × specific heat capacity × temperature change
Where:
Q is the energy in joules
mass is the mass of the substance in grams
specific heat capacity is the amount of energy required to raise the temperature of 1 gram of the substance by 1 degree Celsius
temperature change is the difference in temperature between the initial and final states
In this case, we are dealing with water, which has a specific heat capacity of approximately 4.184 J/g°C. We want to find the energy required to heat 800.0g of water from 20.0°C to its boiling point.
First, we calculate the temperature change by subtracting the initial temperature from the boiling point. The boiling point of water is typically 100°C. Therefore, the temperature change is 100°C - 20.0°C = 80.0°C.
Now, we can plug the values into the formula:
Q = mass × specific heat capacity × temperature change
Q = 800.0g × 4.184 J/g°C × 80.0°C
Now, multiply the values to get the result:
Q = 267,520 J
Since the question asks for the energy in kilojoules, we can convert the result:
267,520 J ÷ 1000 = 267.52 kJ
Therefore, it takes approximately 267.52 kJ of energy to bring 800.0g of water from 20.0°C to its boiling point.