Two hunters shoot at the same duck. The probability of the first hunter hitting the duck is 0.2.

The probability of the second hunter hitting the duck is 0.75. Hitting the duck results in its death.
What is the probability of the duck being killed?

possible outcomes:

MH
HM
HH --- allowing for the case they both hit it

prob = (.8)(.75) + (.2)(.25) + (.2)(.75)
= ....

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thanks Reiny, the buttons were pushed

To find the probability of the duck being killed, we need to consider the probabilities of both hunters hitting the duck.

P(duck being killed) = P(first hunter hitting the duck) AND P(second hunter hitting the duck)

The word "AND" suggests we need to multiply the probabilities together.

P(duck being killed) = P(first hunter hitting the duck) * P(second hunter hitting the duck)

Given that the first hunter's probability of hitting the duck is 0.2 (or 20%), and the second hunter's probability is 0.75 (or 75%), we can substitute these values into the equation:

P(duck being killed) = 0.2 * 0.75 = 0.15

So, the probability of the duck being killed is 0.15, which is equivalent to 15%.