A box is pushed across a horizontal table by a boy applying a force of 32 N to the box. A force of friction of magnitude 19 N acts opposite the direction of motion. A stiff wind also opposes the box’s motion. What force does the box exert on the boy’s hand?
19
A box is pushed across a horizontal table by a boy applying a force of 32 N to the box. A force of friction of magnitude 19 N acts opposite the direction of motion. A stiff wind also opposes the box’s motion. What magnitude of force does the box exert on the boy’s hand?
13
To determine the force that the box exerts on the boy's hand, we can use Newton's third law of motion, which states that for every action, there is an equal and opposite reaction.
In this scenario, the action is the force applied by the boy's hand on the box, and the reaction is the force exerted by the box back onto the boy's hand.
Since the box is moving horizontally across the table, we know that the force applied by the boy's hand (32 N) is greater than the force of friction (19 N) and the wind's opposing force. This means that the net force acting on the box is the difference between the applied force and the force of friction:
Net force = Applied force - Force of friction
Net force = 32 N - 19 N
Net force = 13 N
According to Newton's third law, the box exerts an equal and opposite force on the boy's hand. Therefore, the force exerted by the box on the boy's hand is also 13 N.