A swimming pool is 10 m long, 8 m wide, and 1.5 m deep. The interior of the pool will be painted with water resistant paint. How much area will be covered with the paint?
2(10 * 1.5) + 2(8 * 1.5) + (10 * 8) = _____ square meters
To find the area that will be covered with the water-resistant paint, we need to find the total surface area of the swimming pool.
The pool has four sides, a floor, and a ceiling, so we need to calculate the area of each of these components separately and then add them together.
1. The area of the floor can be found by multiplying the length (10 m) by the width (8 m), giving us 10 m * 8 m = 80 square meters.
2. The area of the ceiling is the same as the floor since it has the same dimensions, which is also 80 square meters.
3. The area of each side can be calculated by multiplying the length (10 m) by the depth (1.5 m), which gives us 10 m * 1.5 m = 15 square meters per side. Since there are four sides, the total area of the sides is 15 sqm * 4 = 60 square meters.
Now, we can add up these areas to find the total surface area:
Floor area + Ceiling area + Side area = 80 sqm + 80 sqm + 60 sqm = 220 square meters.
Therefore, the interior of the swimming pool will be covered with 220 square meters of water-resistant paint.