You toss a quarter straight up. It takes about 2.6 seconds for it to land back on your hand at the same height you tossed it. Find the speed at which you tossed the quarter.
Tr = 2.6/2 = 1.3 s = Rise time.
V = Vo + g*Tr.
V = 0 @ max h.
g = -9.8 m/s^2.
Tr = 1.3 s.
Vo = ? (m/s).
just multiply the a(t) so
9.8(1.3)=12.74 and just keep it positive
To find the speed at which you tossed the quarter, we can use the equation of motion for a freely falling object:
v = u + gt,
where:
v = final velocity (in this case, the velocity when the quarter lands back on your hand, which is 0 m/s because it is at rest)
u = initial velocity (the velocity at which you tossed the quarter, which is what we need to find)
g = acceleration due to gravity (approximately 9.8 m/s^2)
t = time taken (2.6 seconds)
Rearranging the equation to solve for u:
u = (v - gt)
Plugging in the known values:
u = (0 - 9.8 * 2.6)
u = -25.48
The negative sign indicates that the initial velocity was in the opposite direction of the final velocity (upward in this case).
Therefore, the speed at which you tossed the quarter is approximately 25.48 m/s.