How many is moles are in 0.5L of a 3.0M solution of sodium chloride? Sodium chloride dissociates into 2 osmoles per mole.
I'm having trouble setting this up. My teacher couldn't explain it clear enough and neither does the book.
And apparently you don't know what subject you're taking.
Yes I do. This is part of my physiology class. Not every professor has the same structure to their lectures
To determine the number of moles of sodium chloride (NaCl) in the given solution, you need to use the formula:
moles = Molarity × Volume
First, let's set up the equation using the given values:
Molarity (M) = 3.0 M
Volume (V) = 0.5 L
Now, substitute these values into the formula:
moles = 3.0 M × 0.5 L
To proceed, you need to consider that the given concentration of 3.0 M refers to the concentration of sodium chloride ions, not the concentration of moles of NaCl itself.
Since NaCl dissociates into 2 osmoles per mole, the concentration of NaCl in moles can be calculated by dividing the concentration of sodium chloride ions by 2.
moles (of NaCl) = (3.0 M sodium chloride ions) / 2
moles (of NaCl) = 1.5 M
Now, you can substitute this into the equation:
moles = 1.5 M × 0.5 L
Finally, perform the calculation:
moles = 0.75 mol
So, there are 0.75 moles of sodium chloride in 0.5L of a 3.0M solution.