a motorboat accelerates uniformly from a velocity of 6.5m/s the west to velocity of 1.5m/s to the west if its acceleration was 2.7m/s^2 to the east how for did it travel daring the acceleration

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To find how far the motorboat traveled during the acceleration, we can use the following formula:

distance = (final velocity^2 - initial velocity^2) / (2 * acceleration)

Given:
Initial velocity (u) = 6.5 m/s to the west
Final velocity (v) = 1.5 m/s to the west
Acceleration (a) = -2.7 m/s^2 (negative sign indicates acceleration in the opposite direction, i.e., to the east)

Let's substitute the values into the formula:

distance = (1.5^2 - 6.5^2) / (2 * (-2.7))

Simplifying the equation:

distance = (-20.75) / (-5.4)

The negative signs in the equation cancel each other out:

distance = 20.75 / 5.4

Calculating the result:

distance ≈ 3.84 meters

Therefore, the motorboat traveled approximately 3.84 meters during the acceleration.