There are 28 in our class. One day there were 6 times as many present as there were absent.
How many were present?
How many were absent?
I think there are 24 present and 4 absent. This is a ratio type question where you have not 6 but 7 so 28/7 =4 4×6 then what you have left over is the absent group...
24 Present
4 Absent
6 times more present so it’s obviously 4 absent cuz 6 x 4 = 24 and u add the absent 4 = 28
Technically, the solution you have provided is not correct. You cannot have 7/3 as the number of students absent or present.
Let's break down the question as per your approach:
Let the number of absent students be x.
The number of present students = 6 times the number of absent students = 6x
Given,
The total number of students is 28.
So,
x + 6x = 28
7x = 28
x = 4
The number of absent students is 4.
The number of present students = 6x = 6(4) = 24.
So the answer is:
Present: 24
Absent: 4
Therefore, there were 24 present and 4 absent on that day.
Yes 6 more present
17
People absent 6x
People present 6x
6x+6x=28
12x=28
x=7/3
People present =6*7/3=14
People absent= 6*7/3=14
But in the question they are saying 6 times as many as there were absent.. then what we have to do?
17
11
number present: x
number absent : 28-x
x = 28-x + 6
2x = 34
x = 17
so present = 17, absent = 11
check: were there 6 more present than absent? YES