there are 40 bikes inspected. If 15 need new tires and 26 need gear repairs.
-what is the greatest number of bikes that could have needed both repairs?
-The least number that could have needed both?
-Greatest number that could have needed neither repair?
No more than 15 will need both repairs.
Since 15 + 26 = 41, at least one will need both.
40 - 26 = 14 could need neither.
- Well, catch me riding a unicycle because I'm ready with some answers! If 15 bikes need new tires and 26 need gear repairs, we can start by assuming that those 15 bikes with new tires are also part of the 26 bikes needing gear repairs. So, the greatest number of bikes that could have needed both repairs is 15.
- As for the least number, wink wink, nudge nudge, we can assume that there are no bikes needing both repairs. So, the least number of bikes that could have needed both repairs is 0.
- Finally, for the greatest number that could have needed neither repair, let's do some calculations. Since there are 40 bikes in total and we know that 15 need new tires and 26 need gear repairs, we can subtract those numbers from the total: 40 - 15 - 26 = 40 - 41 = -1. Since you can't have negative bikes, the greatest number of bikes that could have needed neither repair is 0.
To find the greatest number of bikes that could have needed both repairs, we need to find the smallest number of bikes that need either tires or gear repairs. In this case, since 15 bikes need new tires and 26 bikes need gear repairs, the greatest number of bikes that could have needed both repairs is the minimum of these two numbers, which is 15.
To find the least number of bikes that could have needed both repairs, we need to find the maximum number of bikes that need both tire and gear repairs. In this case, since there are only 40 bikes and 15 need new tires, the least number of bikes that could have needed both repairs is the maximum of these two numbers, which is 15.
To find the greatest number of bikes that could have needed neither repair, we need to subtract the total number of bikes needing both repairs from the total number of bikes. In this case, there are 40 bikes and 15 bikes needing both repairs, so the greatest number of bikes that could have needed neither repair is 40 - 15 = 25.
To find the answers to these questions, we need to analyze the given information.
First, let's find the greatest number of bikes that could have needed both repairs.
We know that 15 bikes need new tires and 26 bikes need gear repairs. To find the greatest number of bikes that could have needed both repairs, we need to determine the overlap between the two groups, as this represents the maximum number of bikes that needed both repairs.
To do this, we take the smaller of the two numbers, which is 15 in this case. So, the greatest number of bikes that could have needed both repairs is 15.
Next, let's find the least number of bikes that could have needed both repairs.
Following the same logic, we need to determine the overlap between the two groups to find the minimum number of bikes that needed both repairs. In this case, the maximum number of bikes that needed both repairs is determined by the number of bikes needing gear repairs, which is 26.
Therefore, the least number of bikes that could have needed both repairs is 26.
Lastly, let's find the greatest number of bikes that could have needed neither repair.
To calculate this, we need to subtract the number of bikes that need both repairs (26) and the number of bikes that need either new tires (15) or gear repairs (26) from the total number of bikes inspected (40).
Therefore, the greatest number of bikes that could have needed neither repair is:
Total bikes inspected - (Bikes needing new tires + Bikes needing gear repairs - Bikes needing both repairs) = 40 - (15 + 26 - 26) = 40 - 15 = 25.
Hence, the greatest number of bikes that could have needed neither repair is 25.