If Company A rents a truck for $100 per day plus 0.50 per mile and Company B rents the same truck for $60.00 per day plus 0.60 per mile how many miles must you drive for Company A to be a better deal
100+0.50=
60+0.60 =
To find out how many miles you must drive for Company A to be a better deal, we need to compare the total costs for both companies.
Let's assume the number of miles driven is represented as 'x'.
For Company A:
Total Cost = $100 (base daily rate) + $0.50 (per mile rate) * x (miles driven)
Total Cost = $100 + $0.50x
For Company B:
Total Cost = $60 (base daily rate) + $0.60 (per mile rate) * x (miles driven)
Total Cost = $60 + $0.60x
To determine when Company A is a better deal, we need to compare the two total costs:
$100 + $0.50x < $60 + $0.60x
We can simplify this inequality:
$0.50x - $0.60x < $60 - $100
-$0.10x < -$40
Let's divide both sides of the inequality by -0.10 (which is the same as multiplying by -10, and when we multiply by a negative number, we need to flip the inequality sign):
x > 400
So, when you drive more than 400 miles, Company A becomes a better deal.
100 + .5 m = 60 + .6 m
.1 m = 40
m = 400