mechanics: simple harmonic oscillation

Consider an ideal spring that has an unstretched length ℓ and a spring constant k. Suppose the spring is attached to a mass m that lies on a horizontal frictionless surface. The spring-mass system is compressed a distance of x_0 from equilibrium and then released with an initial speed v_0 toward the equilibrium position.

What is the maximum distance the spring will be stretched?

I tried conservation of energy but v_0 can't be used in the solution so I'm at a lost as to what to do.

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  1. x = a sin w t + b cos wt
    v = a w cos wt - b w sin w t

    omega = w = sqrt(k/m)
    at t = 0
    x = -xo
    v = dx/dt = vo

    - xo = b
    + vo = a w or a = vo/w

    so x = (vo/w) sin w t - xo cos wt

    now I could say
    magnitude (or amplitude) = sqrt (vo^2/w^2 + xo^2) which is max motion from equilibrium

    = sqrt (vo^2 m/k + xo^2)

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  2. but how to I eliminate v_0?

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  3. never mind I typed it wrong. Thanks!

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