Calculate the volume at STP of these compounds 1,5 mol oxygen gas
at stp one mol is 22.4 liters
so 1.5 mol is
1.5 * 22.4 = 33.6 Liters
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http://hyperphysics.phy-astr.gsu.edu/hbase/kinetic/idegas.html
To calculate the volume of a gas at STP (Standard Temperature and Pressure), we can use the ideal gas law. The ideal gas law equation is:
PV = nRT
Where:
- P is the pressure of the gas (in atm),
- V is the volume of the gas (in liters),
- n is the number of moles of the gas,
- R is the ideal gas constant (0.0821 L·atm/(mol·K)),
- T is the temperature of the gas (in Kelvin).
At STP, the conditions are 1 atm of pressure and 273.15 K (0 degrees Celsius or 32 degrees Fahrenheit) of temperature.
Given that we have 1.5 mol of oxygen gas, we can substitute the known values into the ideal gas law equation and solve for V.
P = 1 atm
n = 1.5 mol
R = 0.0821 L·atm/(mol·K)
T = 273.15 K
Substituting these values:
(1 atm) * (V) = (1.5 mol) * (0.0821 L·atm/(mol·K)) * (273.15 K)
Simplifying:
V = (1.5 mol * 0.0821 L·atm/(mol·K) * 273.15 K) / 1 atm
Calculating:
V = 33.4 L
Therefore, the volume of 1.5 mol of oxygen gas at STP is approximately 33.4 liters.