math

Find x

1) x^2*23y^2 = 1.78x10^32*z

2) 1.3*10^-4 x=4.7/x -6.3*10^-3

Please help

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  1. x^2*23y^2 = 1.78x10^32*z
    x^2 = (1.78x10^32 z)/(23y^2)
    x^2 = 7.739x10^30 z/y^2
    x = 2.782x10^15 √z/y

    Ok. I'll take it as written

    (1.3*10^-4 x) = (4.7/x) - 6.3*10^-3
    1.3*10^-4 x^2 = 4.7 - 6.3*10^-3 x
    0.00013x^2 + 0.0063x - 4.7 = 0
    x = -215.91, 167.45

    I see you're still using x for both a variable and multiplication

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  2. How can you get the answer

    x = -215.91, 167.45

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