The sum of age of asha and musa is 50 years.If ten years ago the age of musa was twice of asha find their present age
a+m = 50
m-10 = 2(a-10)
Now just solve for a and m.
ran is twice as old as john. in12 years time their combined ages will be 6 times johns present age. what are their present ages
To find the present age of Asha and Musa, we'll use the given information and set up equations based on it.
Let's assume that Asha's present age is 'x' years, and Musa's present age is 'y' years.
According to the given information:
1. The sum of their ages is 50 years, so we have the equation: x + y = 50.
2. Ten years ago, Musa's age was twice Asha's age. So, we have the equation: (y - 10) = 2(x - 10).
To solve these equations, we'll use the method of substitution:
1. Rearrange the equation x + y = 50 to express x in terms of y:
x = 50 - y.
2. Substitute this value of x in the second equation:
(y - 10) = 2((50 - y) - 10).
Simplifying the equation:
y - 10 = 2(40 - y).
y - 10 = 80 - 2y.
Combine like terms:
3y - 10 = 80.
Add 10 to both sides:
3y = 90.
Divide by 3:
y = 30.
Now that we know Musa's age (y) is 30 years, we can substitute this value into the equation x + y = 50 to find Asha's age:
x + 30 = 50.
x = 20.
So, Asha's present age is 20 years, and Musa's present age is 30 years.