A 60 kg soccer player kicks a stationary 0.4 kg ball giving it a speed of 14 m/s. The player's foot is in contact with the ball for 0.08 second. What is the average force on the ball?

P.S What formula/s should I use?

a = (V-Vo)/t = m/s^2.

V = 14 m/s.
Vo = 0.
t = 0.08 s.
Solve for a.

F = M*a.

F = M*a.

M = 0.4 kg.

To find the average force on the ball, you can use Newton's second law of motion, which states that Force (F) is equal to mass (m) multiplied by acceleration (a). In this case, the acceleration can be determined using the equation for average acceleration: a = (final velocity - initial velocity) / time.

Given:
Mass of the player (m1) = 60 kg
Mass of the ball (m2) = 0.4 kg
Initial velocity of the ball (u) = 0 m/s (as it is stationary)
Final velocity of the ball (v) = 14 m/s
Time of contact (t) = 0.08 s

To calculate acceleration (a):
a = (v - u) / t
a = (14 m/s - 0 m/s) / 0.08 s
a = 175 m/s^2

Now we can calculate the force (F) on the ball:
F = m2 * a
F = 0.4 kg * 175 m/s^2
F = 70 N

Therefore, the average force on the ball is 70 Newtons (N).