A syrup is added to an empty container with a mass of 104.70 g . When 0.140 pint of syrup is added, the total mass of the container and syrup is 150.01 g . (1 qt = 2 pt)
0.140 pint= 66.2 mL
150.01g mass container and syrup
104.70g mass empty container
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45.31 mass syrup
d=m/v I cant figure how to work this problem for the life of me. Someone please help
150.01 - 104.70 = 45.31 grams of syrup
.140 pint = 66.2 mL true
so
density = 45.31 grams/66.2 mL
= 0.684 grams/mL = 0.684 grams/cubic centimeter
To calculate the density of the syrup, you can use the formula:
density = mass / volume
In this case, we have the mass of the syrup as 45.31 g. Now, we need to find the volume of the syrup.
Since we know that 0.140 pint of syrup is equal to 66.2 mL, we can convert the volume to liters by dividing by 1000 (since there are 1000 mL in a liter). So,
volume = 66.2 mL / 1000 = 0.0662 L
Now, we can substitute the values into the density formula:
density = 45.31 g / 0.0662 L
Calculating this, we find that the density of the syrup is approximately 685.56 g/L.
To calculate the density (d), we can use the formula:
d = mass / volume
Given that the mass of the syrup is 45.31 g and the volume is 66.2 mL (or 0.0662 L), we can plug these values into the formula:
d = 45.31 g / 0.0662 L
Now, let's calculate the density:
d = 687.5 g/L
Therefore, the density of the syrup is 687.5 g/L.