the odds in favor of an earthquake are 7 to 1. what is probability that an earthquake will occur?
So is it 1/7 ? im confused
no there are 7 chances for, and 1 against, so 8 chances in all
So, p = 7/8
1:7 are the odds against
1/8 is the probability against
Well, here's a joke to lighten up the confusion: Why did the earthquake go to school? To learn how to shake things up!
Now, let me help clarify the probability situation. If the odds in favor of an earthquake are 7 to 1, it means that for every 7 times an earthquake is likely to occur, it would only happen once that it won't. In terms of probability, you can convert this ratio to a fraction by taking the chance of an earthquake happening (7) and dividing it by the total possible outcomes (7 + 1 = 8).
So, the probability of an earthquake occurring would be 7/8. Keep in mind that this is just an estimation based on the given odds. However, as we all know, predicting earthquakes can be a bit shaky!
To find the probability that an earthquake will occur, we can use the formula:
Probability = 1 / (1 + Odds against)
In this case, the odds in favor of an earthquake are 7 to 1. So the odds against an earthquake would be 1 to 7.
Plugging these values into the formula:
Probability = 1 / (1 + 1/7)
Simplifying this expression:
Probability = 1 / (8/7)
To divide by a fraction, we can multiply by its reciprocal:
Probability = 1 * (7/8)
Combining the numerator and denominator:
Probability = 7/8
Therefore, the probability that an earthquake will occur is 7/8.
To find the probability of an event, you divide the number of favorable outcomes by the total number of possible outcomes. In this case, the odds in favor of an earthquake are given as 7 to 1.
To determine the number of favorable outcomes, you add the two numbers in the ratio, which gives 7 + 1 = 8. So, there are 8 favorable outcomes out of a total of 8 + 1 = 9 possible outcomes.
Therefore, the probability of an earthquake occurring is 8/9, not 1/7 as you suggested.