An airplane has a takeoff speed of 66m/s. Assuming a constant acceleration of 1.62m/s^2, how long is the plane accelerating down the runway?
To find the time the plane is accelerating down the runway, we can use the equation of motion:
v = u + at
Where:
v = final velocity (takeoff speed) = 66 m/s
u = initial velocity = 0 m/s (since the plane starts from rest)
a = acceleration = 1.62 m/s^2
t = time
Rearranging the equation, we have:
t = (v - u) / a
Substituting the given values, we have:
t = (66 m/s - 0 m/s) / 1.62 m/s^2
Simplifying the equation:
t = 66 m/s / 1.62 m/s^2
t ≈ 40.74 s
Therefore, the plane is accelerating down the runway for approximately 40.74 seconds.