the probability that a randomly selected 4 year old male feral cat will live to be 5 years old is 0.87886. (a)what is the probability that two randomly selected male 4 yr old cats will live to be 5.(b) what is the probability that six randomly selected male cats will live to be 5.
A=
B=
.4564
(a) To find the probability that two randomly selected male 4-year-old cats will live to be 5, we can use the multiplication rule for independent events.
Since the probability of one cat living to be 5 is 0.87886, the probability of two cats living to be 5 is given by:
A = 0.87886 * 0.87886
A = 0.7713
Therefore, the probability that two randomly selected male 4-year-old cats will live to be 5 is 0.7713.
(b) To find the probability that six randomly selected male cats will live to be 5, we can again use the multiplication rule for independent events.
Since the probability of one cat living to be 5 is 0.87886, the probability of six cats living to be 5 is given by:
B = 0.87886^6
B = 0.5482
Therefore, the probability that six randomly selected male cats will live to be 5 is 0.5482.
To find the probability in both parts (a) and (b), you need to assume that the events are independent. This means that the survival of one male cat does not affect the survival of another.
(a) To find the probability that two randomly selected male 4-year-old cats will live to be 5, you need to multiply the individual probabilities together.
A = Probability of one cat living to be 5 * Probability of another cat living to be 5
A = 0.87886 * 0.87886
A = 0.7712605796
Therefore, the probability that two randomly selected male 4-year-old cats will live to be 5 is approximately 0.771.
(b) To find the probability that six randomly selected male cats will live to be 5, you again need to multiply the individual probabilities together.
B = Probability of cat 1 living to be 5 * Probability of cat 2 living to be 5 * Probability of cat 3 living to be 5 * Probability of cat 4 living to be 5 * Probability of cat 5 living to be 5 * Probability of cat 6 living to be 5
B = 0.87886^6
B = 0.5869110912
Therefore, the probability that six randomly selected male cats will live to be 5 is approximately 0.587.