Will you please help me write this equation in net ionic form.
I2(s)+Na2S2O3(aq)-->Na2S2O4(aq) +NaI(aq)
Surely you made a typo. I think that is I2(s) + Na2S2O3(aq)=>Na2S4O6(aq) + NaI(aq). The net ionic equation for my revised equation is
I2 + 2S2O3^2- --> S4O6^2- + 2I^-
According to the following thermochemical equation, what mass of H2O (in g) must form in order to produce 975 kJ of energy?
SiO2(s) + 4 HF(g) → SiF4(g) + 2 H2O(l) ΔH°rxn = -184 kJ
Sure! To write the above equation in net ionic form, we need to separate the soluble compounds into their respective ions and leave the insoluble compound as a solid.
The balanced equation is:
I2(s) + 2Na2S2O3(aq) → Na2S2O4(aq) + 2NaI(aq)
Step 1: Write the balanced molecular equation:
I2(s) + 2Na2S2O3(aq) → Na2S2O4(aq) + 2NaI(aq)
Step 2: Break down all the soluble compounds into their ions:
I2(s) + 2Na+(aq) + S2O3^2-(aq) → Na2S2O4(aq) + 2Na+(aq) + 2I^-(aq)
Step 3: Eliminate the spectator ions (ions that appear on both sides without undergoing any change) from both sides of the equation:
I2(s) + S2O3^2-(aq) → Na2S2O4(aq) + 2I^-(aq)
Therefore, the net ionic equation is:
I2(s) + S2O3^2-(aq) → Na2S2O4(aq) + 2I^-(aq)
Sure, I'd be happy to help you write the equation in net ionic form.
To write the equation in net ionic form, we need to first write the complete ionic equation and then eliminate the spectator ions, which are the ions that appear on both sides of the equation. The remaining ions will form the net ionic equation.
Let's start with the balanced chemical equation:
I2(s) + Na2S2O3(aq) → Na2S2O4(aq) + NaI(aq)
Now let's write the complete ionic equation by breaking down the soluble ionic compounds into their ions:
I2(s) + 2 Na+(aq) + S2O3^2-(aq) → Na2S2O4(aq) + 2 Na+(aq) + I^-(aq)
In the complete ionic equation, we can identify the spectator ions, which are the ions that appear on both sides of the equation: Na^+(aq).
To write the net ionic equation, we exclude the spectator ions:
I2(s) + S2O3^2-(aq) → Na2S2O4(aq) + I^-(aq)
So, the net ionic equation for the reaction is:
I2(s) + S2O3^2-(aq) → Na2S2O4(aq) + I^-(aq)
This is the net ionic form of the equation.