solution A was prepared by dissolving 0.63g of HNO3 in 100cm3 solution. Solution B is a sodium calcium hydroxide solution of unknown concentration. state a balanced chemical equation for the reaction
Trick question. No reaction, all reactants and possible products (Ca(NO3)2 are soluble in the water present. Something has to be insoluble coming out of solution to be a reaction.
what are two precautions for this experiment
To write a balanced chemical equation for the reaction between solution A (HNO3) and solution B (sodium calcium hydroxide), we need to first identify the chemical formulas of the reactants and products.
The chemical formula of nitric acid, HNO3, consists of one hydrogen atom (H), one nitrogen atom (N), and three oxygen atoms (O). Sodium calcium hydroxide is a compound formed by the combination of sodium hydroxide (NaOH) and calcium hydroxide (Ca(OH)2).
So, the reactants in the chemical equation are:
HNO3 + NaOH + Ca(OH)2
Now, let's identify the products of the reaction. Nitric acid (HNO3) is an acid, which means it will react with hydroxide ions (OH-) to produce water (H2O) and a salt. In this case, since we have sodium hydroxide and calcium hydroxide in solution B, the products will be water and the corresponding sodium and calcium salts. The sodium salt is sodium nitrate (NaNO3), and the calcium salt is calcium hydroxide (Ca(OH)2).
Thus, the balanced chemical equation for the reaction can be written as:
HNO3 + NaOH + Ca(OH)2 -> NaNO3 + Ca(OH)2 + H2O
(Note: The calcium hydroxide appears on both sides of the equation as it does not undergo any chemical change during the reaction.)
Remember, when balancing the equation, make sure that the number of atoms of each element is the same on both sides.