A 15.00ml of NaoH was titrated to the stoichiometric end point with 17.40ml of 0.23M HCL. What is the molarity of NaoH in the solution?. Calculate the mass of NaoH in 15.00ml solution.[H=1, Cl=35.5, Na=23,O=16].
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To find the molarity of NaOH in the solution, we need to use the concept of stoichiometry and the balanced equation of the reaction between NaOH and HCl.
The balanced equation is:
NaOH + HCl → NaCl + H2O
From the balanced equation, we can see that the mole ratio between NaOH and HCl is 1:1, which means that 1 mole of NaOH reacts with 1 mole of HCl.
Step 1: Calculate the number of moles of HCl used.
The volume of HCl solution used is 17.40 ml. To convert this to moles, we need to use the molarity (M) of HCl, which is 0.23 M (moles per liter).
Moles of HCl = Molarity × Volume (in liters)
Moles of HCl = 0.23 M × (17.40 ml/1000 ml)
Moles of HCl = 0.003?)82 mol
Step 2: Since the reaction is 1:1, the number of moles of NaOH used is also 0.003?)82 mol.
Step 3: Calculate the molarity of NaOH in the solution.
Molarity of NaOH = Moles of NaOH / Volume of NaOH solution (in liters)
Volume of NaOH solution = 15.00 ml = 15.00 ml / 1000 ml = 0.015 L
Molarity of NaOH = 0.003?)82 mol / 0.015 L
Molarity of NaOH = 0.229 M
Therefore, the molarity of NaOH in the solution is 0.229 M.
To calculate the mass of NaOH in the 15.00 ml solution, we need to use the molarity and the molar mass of NaOH.
Step 1: Calculate the number of moles of NaOH.
Moles of NaOH = Molarity × Volume (in liters)
Moles of NaOH = 0.229 M × 0.015 L
Moles of NaOH = 0.003?)45 mol
Step 2: Calculate the molar mass of NaOH.
Molar mass of NaOH = (1 × 23) + (1 × 16) + (1 × 1)
Molar mass of NaOH = 23 + 16 + 1
Molar mass of NaOH = 40 g/mol
Step 3: Calculate the mass of NaOH in the 15.00 ml solution.
Mass of NaOH = Moles of NaOH × Molar mass of NaOH
Mass of NaOH = 0.003?)45 mol × 40 g/mol
Mass of NaOH = 0.113 g
Therefore, the mass of NaOH in the 15.00 ml solution is 0.113 g.