If x + y + z = 26, find the value of (y-2) + (z+3) + (x-3). I was so confused on this question and didn't even know where to start. Please help me!
get rid of the parentheses and rearrange things a bit:
(y-2) + (z+3) + (x-3)
y-2+z+3+x-3
x+y+z-2+3-3
But, you know that x+y+z = 26, so that gives you
26-2+3-3
24
Thank you so much! That really helped!
To find the value of (y-2) + (z+3) + (x-3), we can simplify the expression step by step.
We know that x + y + z = 26, so we can substitute this value into our expression:
(y-2) + (z+3) + (x-3) = (y + z + x) + ( -2 + 3 - 3)
Now, substituting the value of x + y + z = 26, we have:
(y + z + x) + ( -2 + 3 - 3) = 26 + ( -2 + 3 - 3)
Next, we can simplify the expression inside the parentheses:
26 + ( -2 + 3 - 3) = 26 + (-2)
Now, we can perform the addition:
26 + (-2) = 24
So, the value of (y-2) + (z+3) + (x-3) is 24.
To get to this answer, we substituted the value of x + y + z into the expression and then simplified it step by step, following the order of operations.