A bolt of mass 0.3 kg falls from The ceiling of an elevator moving down with a uniform speed of 7m/s.It hits the floor of the elevator and does not rebound.What is the heat produced by the impact?g=9.8m/s to the power 2 .
To calculate the heat produced by the impact, we can use the concept of kinetic energy.
The kinetic energy (KE) of an object can be calculated using the formula: KE = (1/2) * mass * velocity^2.
First, let's calculate the initial kinetic energy of the bolt. Given that the mass (m) is 0.3 kg and the velocity (v) is 7 m/s, we can use the formula:
KE_initial = (1/2) * 0.3 kg * (7 m/s)^2
KE_initial = 0.5 * 0.3 kg * 49 m^2/s^2
KE_initial = 7.35 J (Joules)
Now, let's calculate the final kinetic energy of the bolt when it hits the floor and comes to rest. Since the bolt does not rebound, all of its initial kinetic energy is converted into heat.
Therefore, the heat produced by the impact is equal to the initial kinetic energy:
Heat = KE_initial = 7.35 J (Joules)
So, the heat produced by the impact is 7.35 Joules.