Is initial velocity can be negative?
in this case,
A stone is dropped from a ballon while ascending at the rate of 8mps. The stone reaches the ground in 6 sec. What is the height of the balloon when the stone was dropped?
What is the sign for the initial velocity? Can someone help me with this? Im really confused.
See previous post: Sat, 8-22-15, 11:06 AM
I saw it, but why is it the initial velocity is negative?
The initial velocity is negative,because
the stone was moving upward before it began to free fall. In other words, the balloon containing the stone was moving upward as the stone began to move downward.
If the stone had been THROWN downward
from a stationary object, the initial
velocity would have been positive.
When dealing with motion, the initial velocity can indeed be negative. The sign of the initial velocity indicates the direction of the object's motion.
In this case, the stone is dropped from a balloon while the balloon is ascending at a rate of 8 m/s. As the stone is dropped, it starts moving in the opposite direction of the balloon's ascent, which means its initial velocity will be negative.
To solve the problem and find the height of the balloon when the stone was dropped, we can use the equation of motion:
h = ut + (1/2)gt^2
Given:
Initial velocity (u) = -8 m/s (negative because it's in the opposite direction)
Time (t) = 6 s
Acceleration due to gravity (g) = 9.8 m/s^2 (assuming no air resistance)
Plugging these values into the equation, we get:
h = (-8)(6) + (1/2)(9.8)(6^2)
h = -48 + 294 = 246 meters
Therefore, the height of the balloon when the stone was dropped is 246 meters.