HENRY, ANDY AND JOE SHARED SOME SWEETS IN THE RATIO 15:12:9 RESPECTIVELY. HENRY HAD 6 MORE SWEETS THAN ANDY. IF ANDY GAVE 9 SWEETS TO JOE, HOW MANY SWEETS WOULD JOE HAVE?
(a+6)/a = 15/12
12(a+6) = 15a
12a+72 = 15a
3a = 72
a = 24
a/j = 12/9, so
24/j = 12/9
j = 18
So, if Andy gave Joe 9, he'd have 27
To find out how many sweets Joe would have after Andy gives him 9 sweets, we need to first determine the number of sweets each person has.
Let's start by assigning a variable to represent the number of sweets Andy has. Let's call it "x."
According to the given information, Henry has 6 more sweets than Andy, so Henry would have x + 6 sweets.
To simplify the problem, let's find the common multiple of the ratios (15:12:9), which is 3. This means that for every 3 units of sweets, Henry would have 15, Andy would have 12, and Joe would have 9.
Now, let's set up an equation to represent the total number of sweets:
15x + 12x + 9x = Total number of sweets
Combining like terms, we have:
36x = Total number of sweets
To find the value of "x," we need more information or an additional equation.