A parking lot has the shape of a parallelogram. The lengths of two adjacent sides are 70meters and 100meters.
The angle between the two sides is 70o. What is the area of the parking lot?
Dude it's been like 5-6 years nobody has answered this
you should be able to convince yourself that the area of a parallelogram with sides a and b, and angle θ is
ab sinθ
328.892 m^2
To find the area of the parallelogram-shaped parking lot, we can use the formula A = base * height, where base is the length of one of the sides and height is the perpendicular distance between the side and its opposite side.
In this case, since the parking lot is a parallelogram, the base can be either 70 meters or 100 meters. Let's take 70 meters as the base.
To find the height, we can use trigonometry. Since we know the length of one side (70 meters) and the angle between the sides (70 degrees), we can determine the height using the formula: height = base * sin(angle).
Plugging in the values, we get:
height = 70 meters * sin(70 degrees)
Using a scientific calculator or online trigonometric calculator, we find that sin(70 degrees) is approximately 0.9397.
So, the height is approximately 70 meters * 0.9397 = 65.779 meters.
Now, we can calculate the area of the parallelogram:
A = base * height = 70 meters * 65.779 meters = 4604.53 square meters.
Therefore, the area of the parking lot is approximately 4604.53 square meters.