Question

A line rotates in a horizontal plane according to the equation Y = 2t^3- 6t, where Y is the angular position of the rotating line, in radians, and t is the time, in seconds.

Determine the angular acceleration when
t = 2 sec.

Answer 1

position y = 2t^3-6t rad

velocity v = dy/dt = 6t^2-6 rad/s
acceleration a = dv/dt = 12t rad/s^2