# Trig

Find all solutions of the equation in the interval [0,2pi). 2sin theta+1=0.

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1. 2sinθ+1 = 0
2sinθ = -1
sinθ = -1/2
sin π/6 = 1/2, so using that as a reference angle in QIII and QIV, we get the solutions

π + π/6 and 2π - π/6

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posted by Steve

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