Trig

Find all solutions of the equation in the interval [0,2pi). 2sin theta+1=0.
Write answer in radians in terms of pi.

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asked by James
  1. 2sinθ+1 = 0
    2sinθ = -1
    sinθ = -1/2
    sin π/6 = 1/2, so using that as a reference angle in QIII and QIV, we get the solutions

    π + π/6 and 2π - π/6

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    posted by Steve

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