Physics

A bird watcher meanders through the woods, walking 1.07 km due east, 0.533 km due south, and 4.62 km in a direction 50.1 ° north of west. The time required for this trip is 1.451 h. Determine the magnitudes of the bird watcher's (a) displacement and (b) average velocity.

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  1. 1.07 E = <1.07,0>
    .533 S = <0,-0.533>
    4.62 @ W50.1°N = <-2.963,3.644>

    add them all up and you have a final displacement of

    <-1.893,3.111> = 3.642 @ N31.3°W
    now you can figure the velocity

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