A bullet whose mass is 1.0 x 10-3 kg leaves a 5.0 kg rifle with a muzzle velocity of 1.0 x 103 m/s. It strikes a stationary block of wood whose mass is 1.0 kg and remains embedded in it. The kinetic energy of the bullet as it travels towards the wooden block is?
KE = 0.5M*V^2.
M = 1.*10^-3 kg.
V = 1.*10^3 m/s.
Solve for KE.
Acheetan 101m along 41m acceleration 9•5
To find the kinetic energy of the bullet as it travels towards the wooden block, we can use the formula for kinetic energy:
Kinetic Energy = (1/2) * mass * velocity^2
Given:
Mass of the bullet (m1) = 1.0 x 10^-3 kg
Velocity of the bullet (v) = 1.0 x 10^3 m/s
Using the given values, we can calculate the kinetic energy:
Kinetic Energy = (1/2) * (1.0 x 10^-3 kg) * (1.0 x 10^3 m/s)^2
Now, let's solve the calculation step by step:
1. Multiply the velocity by itself:
(1.0 x 10^3 m/s)^2 = (1.0 x 10^3)^2 = 1.0 x 10^6 m^2/s^2
2. Multiply the mass and the squared velocity:
(1/2) * (1.0 x 10^-3 kg) * (1.0 x 10^6 m^2/s^2) = 0.5 x 10^-3 x 10^6 x kg x m^2/s^2
3. Simplify the units:
0.5 x 10^-3 x 10^6 x kg x m^2/s^2 = 0.5 x 10^3 x kg x m^2/s^2
Thus, the kinetic energy of the bullet as it travels towards the wooden block is 0.5 x 10^3 kg·m^2/s^2 or 500 J (Joules).