Ethane burns in limited supply of air to give carbon monoxide. What would be the balanced equation for it?
2C2H6 + 7O2 ==> 4CO2 + 6H2O
in limited air, what reaction does it undergo to form carbon MONOXIDE ?
Well it's probably too late to answer. But if anyone stumble here in future the reaction is "combustion"
To balance the equation for the combustion of ethane (C2H6) in limited supply of air to give carbon monoxide (CO), follow these steps:
Step 1: Write the unbalanced equation:
C2H6 + O2 → CO
Step 2: Count the number of atoms of each element on both sides of the equation.
On the left side, there are:
- 2 carbon (C) atoms
- 6 hydrogen (H) atoms
- 2 oxygen (O) atoms
On the right side, there are:
- 1 carbon (C) atom
- 1 oxygen (O) atom
Step 3: Start balancing the carbon (C) atoms by placing a coefficient in front of CO to match the number of carbon atoms on both sides.
C2H6 + O2 → 2CO
Step 4: Check the hydrogen (H) atoms. On the left side, there are 6 hydrogen atoms, so we need to balance them on the right side by placing a coefficient in front of water (H2O).
C2H6 + O2 → 2CO + 3H2O
Step 5: Finally, balance the oxygen (O) atoms. On the left side, there are 2 oxygen atoms from the O2 molecule and 6 oxygen atoms from the 3H2O molecule for a total of 8 oxygen atoms. To balance the oxygen, place a coefficient in front of O2.
C2H6 + 7/2O2 → 2CO + 3H2O
Since fractions are not commonly used in balanced chemical equations, we multiply all coefficients by 2 to eliminate the fractional coefficient at the beginning:
2C2H6 + 7O2 → 4CO + 6H2O
Therefore, the balanced equation for the combustion of ethane in limited supply of air to give carbon monoxide is:
2C2H6 + 7O2 → 4CO + 6H2O