# problems involving equations

the sum of two numbers is 38. when 8 is added
to twice one of the number, the result is 5 times
the other number. find the number

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1. x+y = 38
8+2x = 5y

Now just solve for x and y

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2. x+y=38
8+2x=5y
8*x=2xy/8
8x/8=2y/8 8x/8-5y/8=3xy/8
x+y=38
2x/8-5y/8
40x-16y/64=24/1
40x-16

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3. 40x-16y=24/x+y=38
40x-16y=0
fom equl
x=31-y
substitute eqn3in 2
40x-16y=0
40(38-y)-16y
78y-38=40=16y
78y-38=40y
-38=40-78y
-38y=-78y
divide both sides by 38
38y/38=78y/38
y=2.05

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