I am a four digit number, I am between 2,000 and 3,000 the digit in the ones place is four times as much as the digit in the thousands place. Only one of the digits are the same. The digit in the tens place is one more than the digit in the hundreds place. All of the digits adds up to 21. (I'm stump on this math question and it's Jayden's homework anyone knows the answer to this let me know A.S.A.P) Thank you!
Just read what they say and start filling in the digits!
I am a four digit number
xxxx
I am between 2,000 and 3,000
2xxx
the digit in the ones place is four times as much as the digit in the thousands place
2xx8
Only one of the digits are the same.
Ya got me what that means.
The digit in the tens place is one more than the digit in the hundreds place.
Now we have digits
(2)(n)(n+1)(8)
All of the digits adds up to 21.
2+n+n+1+8 = 21
n = 5
And the number is
2568
Since it is between 2,000 and 3,000, the thousands number must be two, so ones = 2 * 4 = 8
Let hundreds place = x, then tens = x+1.
2 + x + x+1 + 8 = 21
However, none of the digits are the same.
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To find the four-digit number that meets all the given conditions, we can go step by step:
Step 1: Start with the condition that the number is between 2,000 and 3,000. This means the thousands place digit must be 2.
Step 2: Determine the digit in the ones place, which is four times as much as the digit in the thousands place. Since the thousands place digit is 2, the ones place digit must be 4 times 2, which is 8.
Step 3: Determine the digit in the tens place, which is one more than the digit in the hundreds place. We know that the sum of all the digits is 21, so the hundreds place digit plus the tens place digit must equal 2 + 8 = 10. Since the tens digit is one more than the hundreds digit, we can set up an equation: x + (x+1) = 10
Simplifying the equation gives us 2x + 1 = 10
Subtracting 1 from both sides, we get 2x = 9
Dividing both sides by 2, we find x = 4.5. However, as a four-digit number, each digit must be a whole number, so we cannot have a decimal in the tens place.
Step 4: Since we cannot have a decimal in the tens place, we round 4.5 to the nearest whole number, which is 5. This means the tens place digit is 5.
Step 5: To determine the hundreds place digit, we can use the fact that the sum of all the digits is 21. If we subtract the thousands digit (2), ones digit (8), and tens digit (5) from 21, we get 21 - (2 + 8 + 5) = 21 - 15 = 6. Therefore, the hundreds place digit is 6.
Putting all the digits together, we get the four-digit number as 2,685.
So the answer to Jayden's homework is 2,685.