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Why may the absorbance of a filtrate be higher than it's theoretical concentration?
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Something else in the filtrate that is absorbing at the same wavelength could lead to it but there must be half a dozen other possibilities.
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After isolating the sulfonated product, the filtrate volume is found to be 25.25 mL. A dilution using 1 mL of filtrate and 99 mL
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e = molar absorptivity A = ebc and I assume b (length cell) is 1 cm), then 0.427 = 12,100*C Solve
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If you have an equation for a line, y = 0.15x + 0.010, where y is absorbance and x is concentration in molarity of Fe (2+),
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.065 = .15 x + .01 .15 x = .055 x = 5.5/15
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How would you get the concentration(ppm) of a sample from absorbance?
Absorbance of standard = 2.55 Absorbance of sample = 2.31
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Absorbance std = k*concn std 2.55 = k*8 Solve for k. Absorbance sample = k*concn sample 2.31 = k
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The regression line from a plot of absorbance vs. concentration yields: 𝐴 = 2.31[𝐶] + 0.002. If the absorbance of an
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A = 2.31C + 0.002 0.123 = 2.31C + 0.002 (0.123-0.002)/2.31 = C You solve it.
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The regression line from a plot of absorbance vs. concentration yields: 𝐴 = 2.31[𝐶] + 0.002. If the absorbance of an
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To find the concentration [C] using the regression line equation A = 2.31[C] + 0.002, we need to
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If you have an equation for a line, y = 0.15x + 0.010, where y is absorbance and x is concentration in molarity of Fe (2+),
Top answer:
y = 0.15x + 0.010 y = 0.065 so 0.065 = 0.15x + 0.010. Solve for x. 0.065 - 0.010 = 0.055 = 0.15x so
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two reasons potassium is more concentrated in urine than in the filtrate
why are blood cells and proteins usually not found in
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Oh, potassium, the diva of urine concentration. Here are two reasons why it steals the spotlight: 1.
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okay you talked about using a graph and we made one so this is the formula from it.
y = 2.2019x y = absorbance x= concentration
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Yes, or if you have a graph you should be able to read the concn directly from the graph without any
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Determine the concentration of a dioxin solution whose percent absorbance is 0.40%
This is the resulting: Absorbance Dioxin 0.64
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I am unfamiliar with an absorbance of 0.40%. 0.40, yes, but not the percent. If it really is 0.4%,
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1) If your spectrophotmeter can measure n absorbance up to 1.5, what is the maximum concentration of NADH that you can measure
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A = 1.5, then %T = 31.6%. But questions 1 and 2 can't be answered without knowing what the graph
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