Take element Z = 24 from the periodic table. Ionize it 23 times so that there is only one electron left orbiting around the nucleus. What is the ground state energy of the electron?

To determine the ground state energy of an electron in a specific orbital, we need to know the atomic number of the element, which corresponds to the number of protons in the nucleus. In this case, element Z = 24, which means it has 24 protons.

To find the ground state energy of the electron, we need to determine its position in the electron configuration. Since the electron is ionized 23 times, there is only one electron left in the atom. The electron will occupy the lowest energy level available, which is the first energy level (n = 1).

The energy of an electron in a specific energy level is given by the formula:

E = -13.6 eV / n²

where E is the energy, n is the principal quantum number, and -13.6 eV is the constant representing the ionization energy of hydrogen.

For the ground state energy, we substitute n = 1 into the formula:

E = -13.6 eV / (1)²
E = -13.6 eV

Thus, the ground state energy of the electron in this scenario is -13.6 eV.