Urgent math

pls help out with this example as well.

Find the term containing x^3 in the binomial expansion of
(3x − 3)^10

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  1. the expansion of (a+b)^10 starts out with a^10, so the term with a^3 is C(10,7)a^3b^7

    So, since you have a = 3x and b = -3, that would be

    = 360(27x^3)(-2187)
    = -7085880x^3

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