Geometry

Line MO bisects <LMN, m<LMN =6x-28,m<LMO=x+34. Find m<NMO

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  1. since LMO+NMO = LMN,

    x+34 + NMO = 6x-28
    But, MO bisects LMN, so LMO=NMO
    x+34 + x+34 = 6x-28
    2x+68 = 6x-28
    4x = 96
    x = 24

    Now you can figure the actual degree measures.

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  2. That would makem it

    24 + 34 =58 T NMO = 6(24)-28

    58 + nmo = 144 - 28 = 119

    116- 58 = 58

    Thank you

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  3. neature

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  4. thx

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