3-pentanol is heated with sulphuric acid (H2SO4) to become compound M. Compound M is reacted with Br2/ H2O to form Compound N.

Outline the reaction step and name the compound M and N

Since 3-pentanol is a symmetrical secondary alcohol, treatment with H2SO4 gives the alkene and there is only one possible. That will be 2-pentene and that is M. Then Br2/H2O produces a bromohydrin reaction in which Br adds to one side of the double bond and OH adds to the other. Look up bromohydrin reactions to obtain that product which is N.

Reaction Step 1:

3-Pentanol (C5H12O) is heated with sulfuric acid (H2SO4).

Compound M:
The reaction of 3-pentanol with sulfuric acid produces an alkene called 3-pentene (C5H10). This compound is named compound M.

Reaction Step 2:
Compound M (3-pentene) reacts with Br2 (bromine) and H2O (water).

Compound N:
The reaction of Compound M with bromine and water (Br2/H2O) forms 1,2-dibromopentane (C5H10Br2). This compound is named compound N.

The reaction mentioned involves the conversion of 3-pentanol to compound M using sulfuric acid (H2SO4), followed by the reaction of compound M with bromine (Br2) and water (H2O) to form compound N.

Let's break down the reactions step by step:

1. Conversion of 3-pentanol to compound M:
When 3-pentanol is heated with sulfuric acid (H2SO4), it undergoes an acid-catalyzed dehydration reaction, resulting in the removal of a water molecule (H2O) and the formation of compound M. This is known as an elimination reaction. The reaction can be represented as follows:

3-pentanol + H2SO4 → Compound M + H2O

Compound M is the product of this reaction.

2. Reaction of compound M with Br2/H2O to form compound N:
Compound M is then reacted with bromine (Br2) and water (H2O) to form compound N. In this reaction, the bromine molecule adds across a double bond in compound M, resulting in the formation of a new compound with a bromine group attached to it. This type of reaction is known as an addition reaction. The reaction can be represented as follows:

Compound M + Br2/H2O → Compound N

Compound N is the product of this reaction.

To provide the specific names of compound M and compound N, the molecular structures of the compounds would need to be known.