Algebra ASAP

pls pls help out
A geometric sequence begins
36, 9, 9/4, 9/16, 9/64, . . . .
(a) Find the common ratio r for this sequence.
r =

(b) Find a formula for the nth term an of the sequence.
an =

(c) Find the tenth term of the sequence.
a10 =

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  1. find r by dividing any term by the previous term: r = 9/36 = 1/4

    So, Tn = 36*(1/4)^(n-1) = 144/4^n

    T10 = 144/4^10

    This was pretty straightforward. Looks like you need to review the topic.

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