The perimeter of a rectangle is 62 cm. The length is 5 less 2 times the number x. What is the width?
Is the answer 18?
Width = W.
L = 2W - 5.
2W + 2L = 62 cm.
2W + 2(2W-5) = 62.
2W + 4W - 10 = 62.
6W = 72.
W = 12 cm.
Thank you
Glad I could help.
To find the width of the rectangle, we can use the formula for the perimeter of a rectangle, which is given by:
Perimeter = 2 * (Length + Width)
Given that the perimeter of the rectangle is 62 cm, we can set up the equation as follows:
62 = 2 * (Length + Width)
Now, let's express the length in terms of x. The problem states that the length is 5 less 2 times x. Therefore, we can write the length as:
Length = 5 - 2x
Plugging this into the equation, we have:
62 = 2 * (5 - 2x + Width)
Now, let's simplify the equation:
62 = 10 - 4x + 2 * Width
Rearranging the terms, we get:
62 - 10 + 4x = 2 * Width
Simplifying further, we have:
52 + 4x = 2 * Width
Divide both sides by 2:
26 + 2x = Width
So, the width of the rectangle is given by the equation:
Width = 26 + 2x
Now, if we substitute the given value of x into this equation, we can find the width. You mentioned that x = 18, so substituting this into the equation, we have:
Width = 26 + 2 * 18
Width = 26 + 36
Width = 62
Therefore, the width of the rectangle is 62 cm, not 18 cm.