# physics

A bus accelerates at 2.4 m/s2 from rest for 10 s. It then travels at constant speed for 25 s, after which it slows to a stop with an acceleration of magnitude 1.5 m/s2.
(a) What is the total distance that the bus travels?
(b) What was its average velocity?
If possible, could you explain things and how you got the formulas too? Thank you!

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1. V1 = a*T1 = 2.4 * 10 = 24 m/s.

d1 = 0.5a*T1^2 = 1.2*10^2 = 120 m.
a. d2 = V1*T2 = 24 * 25 = 600 m.

V^2 = V1^2 + 2a*d3 = 0
d3 = -V1^2/2a = -(24^2)/-3 = 192 m.

d = d1+d2+d3 = 120 + 600 + 192 = 912 m. = Total distance traveled.

b. V = V1 + a*T3 = 0.
T3 = -V1/a = -24/-1.5 = 16 s.

T = T1+T2+T3 = 10 + 25 + 16 = 51 s.

V = d/T = 912m/51s. = 17.9 m/s. = Avg.
velocity.

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