C respectively to prepare a 50% (mass by volume) solution of sodium hydroxide (NaOH). 'A' dissolved 50 g of NaOH in 100 ml of water B dissolved 50g of NaOH in 100g of water while C dissolved 50g of NaOH in water to make 100ml of ...

I'm not sure I understand the question. If you want a fill in the blank, C should dissolve 50 g NaOH NaOH in enough H2O to make 100 mL of SOLUTION.

To prepare a 50% (mass by volume) solution of sodium hydroxide (NaOH), we need to calculate the amount of NaOH needed and the volume of water required.

Solution 'A': In this case, 50 g of NaOH is dissolved in 100 ml of water.

Solution 'B': In this case, 50 g of NaOH is dissolved in 100 g of water.

Solution 'C': In this case, 50 g of NaOH is dissolved in water to make 100 ml of solution.

To determine the amount of NaOH in each solution, we use the given mass of 50 g.

For Solution 'A': 50 g of NaOH is dissolved in 100 ml of water. This means the final solution will have a mass of 50 g NaOH + 100 g water = 150 g.

For Solution 'B': 50 g of NaOH is dissolved in 100 g of water. This means the final solution will have a mass of 50 g NaOH + 100 g water = 150 g.

For Solution 'C': 50 g of NaOH is dissolved in water to make 100 ml of solution. The mass of the solution will depend on the density of water. Assuming the density of water is 1 g/ml, the final solution will have a mass of 50 g NaOH + 100 g water = 150 g.

Now, to calculate the concentration of NaOH in each solution, we need to determine the mass of NaOH in relation to the volume of the solution.

For Solution 'A': The volume of the solution is 100 ml. To calculate the concentration, we divide the mass of NaOH (50 g) by the volume of the solution (100 ml): (50 g / 100 ml) x 100% = 50% mass by volume.

For Solution 'B': The volume of the solution is not provided, so we cannot determine the concentration.

For Solution 'C': The volume of the solution is 100 ml. To calculate the concentration, we divide the mass of NaOH (50 g) by the volume of the solution (100 ml): (50 g / 100 ml) x 100% = 50% mass by volume.

Therefore, only Solution 'A' and Solution 'C' have a concentration of 50% (mass by volume) of NaOH.