A car moving with a velocity of 20m/s at 30 degree to the horizontal,what is the component of the velocity along the horizontal?
20 cos30°
=17.3m/s
To find the horizontal component of the velocity, we need to use trigonometry.
The horizontal component of the velocity is given by:
Horizontal component = Velocity * Cos(angle)
Given:
Velocity = 20 m/s
Angle = 30 degrees
Using the formula above:
Horizontal component = 20 * Cos(30)
Using the value of cosine of 30 degrees, which is (√3)/2:
Horizontal component = 20 * (√3)/2
Simplifying:
Horizontal component = 10 * (√3)
Therefore, the component of the velocity along the horizontal is 10√3 m/s.
To find the component of velocity along the horizontal, you need to use trigonometry. Here's how you can solve it step-by-step:
Step 1: Identify the given values:
- Velocity of the car: 20 m/s
- Angle with the horizontal: 30 degrees
Step 2: Visualize the given scenario:
Imagine a right-angled triangle with one side representing the horizontal component of velocity, one side representing the vertical component of velocity, and the hypotenuse representing the actual velocity of the car.
Step 3: Apply trigonometry:
The horizontal component of the velocity is given by the formula:
horizontal component = velocity * cos(angle)
In this case, the velocity is 20 m/s and the angle is 30 degrees. So, using the formula,
horizontal component = 20 m/s * cos(30 degrees)
Step 4: Calculate the answer:
Calculating the value of cos(30 degrees), we get:
cos(30 degrees) = √3/2 (approximately 0.866)
Multiplying this value by the given velocity:
horizontal component = 20 m/s * 0.866
horizontal component ≈ 17.32 m/s
Therefore, the component of the velocity along the horizontal is approximately 17.32 m/s.