Calculus

Differentiate this y = 1 - cos^2 x

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  1. Taking differential with respect to x on both sides d/dx y =d/dx(1-cos^2x) dy/dx = d/dx1 -d/dx(cosx)^2 dy/dx =0 - 2cosx *d/dx cosx. dy/dx= -2cosx*(-sinx) d/dx x dy/dx=2sinxcosx *1 dy/dx=sin2x [d/dx (x) =1] by first principle

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  2. y = 1 - cos^2 x
    y = 1 - (cos x)^2

    dy/dx = -2cosx (-sinx)
    = 2 sinx cosx
    or sin (2x)

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