Three cards are drawn from a deck of 52 playing cards and not replaced. Find the probability of the following:

a). Getting three jacks
b). Getting an ace, a king, and a spade in that order.
c). Getting a club, a spade and a heart in that order.
d). Getting three clubs.

HELP!

a)P(3J)= (4/52)*(3/51)*(2/50)

b)P(A+K+S)= ((4/42)*(4/51)*(13/50))+((4/52)*(4/51)*(12/50))+((4/52)*(4/51)*(11/50))

c)(13/52)*(12/51)*(11/50)

To find the probability of an event, we need to divide the number of favorable outcomes by the number of possible outcomes.

a) To get three jacks, there are 4 jacks in the deck. The first jack can be any of the 4 jacks, the second can be any of the remaining 3 jacks, and the third can be any of the remaining 2 jacks. Since there are 52 cards in total, the probability is:

P(3J) = (4/52) * (3/51) * (2/50)

b) To get an ace, a king, and a spade in that order, there are 4 aces, 4 kings, and 13 spades in the deck. The first card has to be an ace (4/52), the second card has to be a king (4/51), and the third card has to be a spade (13/50). Since the cards are not replaced, the probability is the product of these individual probabilities:

P(Ace, King, Spade) = (4/52) * (4/51) * (13/50)

c) To get a club, a spade, and a heart in that order, there are 13 clubs, 13 spades, and 13 hearts in the deck. The first card has to be a club (13/52), the second card has to be a spade (13/51), and the third card has to be a heart (13/50). Since the cards are not replaced, the probability is the product of these individual probabilities:

P(Club, Spade, Heart) = (13/52) * (13/51) * (13/50)

d) To get three clubs, there are 13 clubs in the deck. The first card can be any of the 13 clubs, the second can be any of the remaining 12 clubs, and the third can be any of the remaining 11 clubs. Since there are 52 cards in total, the probability is:

P(3 Clubs) = (13/52) * (12/51) * (11/50)

You can now calculate the probabilities using these formulas.