drawls this is from the previous post is this correct.
solve the system by subtraction.
5x-3y=13
4x-3y=11
equation#2 woudl be
4x-3y=11
-3y = -4x+11
y = (4)/(3) x - (11)/(3)
so now i substitute it to equation #1
5x - 3((4)/(3)x - (11)/(3)= 13
5x - 4 x +11 = 13
1x + 11 = 13
1x = 13-11
1x= 2
x = 2
now i substitute back into equation #1
5(2)-3y=13
10-3y=13
-3y = 13-10
-3y=3
y=-1
so , my solution would be (2,-1)
am i correct?
Yes, you have solved the system of equations correctly. Your solution of (2, -1) is indeed correct.
To solve the system by subtraction, you eliminated the variable "y" by making the coefficients of "y" the same in both equations. This allowed you to subtract the equations directly to eliminate "y".
Then, you solved for "x" by isolating the variable in one of the equations. In this case, you chose equation #2 since it already had the same coefficient for "y". You rearranged the equation to solve for "y" and obtained y = (4/3)x - (11/3).
Next, you substituted this value of "y" into equation #1 and simplified the equation. By combining like terms, you obtained 1x + 11 = 13, or simply x = 2.
Finally, you substituted the value of "x" back into equation #1 and solved for "y". By simplifying the equation, you obtained -3y = 3, or y = -1.
Therefore, the solution to the system of equations is (2, -1). Well done!