# Algebra 2

Standard form for both equation with steps

16x^2-96x+144+25y^2=400

16x^2+192x+576+25y^2=1600

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## Similar Questions

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Standard form for both equation with steps 16x^2-96x+144+25y^2=400 16x^2+192x+576+25y^2=1600

asked by Spence on August 23, 2015
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Calculate the solution set. x^2+y^2+8x=-15 9x^2+25y^2=225 My work: I did elimination...multiplied -25 to the top equation and got..... -16x^2-200x-600...I then used quadratic formula ... And got -7.5 and -5..... Is -7.5 an

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If P(x,y),F1(3,0), F2(-3,0) a nd 16x^2+25y^2=400, then find PF1+PF2.

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asked by Anonymous on January 12, 2013
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complete factorization y^4-25y^2+144 (^) denotes following number is Power y^4 - 25y^2 + 144 You might try replacing y^2 with x. Therefore your statement becomes: x^2 - 25x + 144 ...which is easier to factor.

asked by deborah on January 23, 2007

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