The rate law for the reaction NO + O3 > NO2 is rate= k[NO][O3]. What will the effect on the reaction rate if the partial pressure of NO is doubled? What will the effect if the partial pressure of O2 is tripled?

Just for clarification: NO will be doubled and O3 would be tripled.

I hardly know what you're clarifying. The rate law, since both NO and O3 are raised to the first power should b e doubled and tripled.

To determine the effect of changes in partial pressure on the reaction rate, you can use the rate law equation.

Given the rate law for the reaction: rate = k[NO][O3]

1. Effect of doubling the partial pressure of NO:
If the partial pressure of NO is doubled, it means that the concentration of NO doubles as well (assuming the temperature and volume remain constant). Therefore, you can write the new rate law equation as:
rate' = k'[2[NO]][O3]

Since the concentration of NO is now doubled, the reaction rate will also double. So, doubling the partial pressure of NO will result in a doubling of the reaction rate.

2. Effect of tripling the partial pressure of O3:
Similarly, if the partial pressure of O3 is tripled, it means that the concentration of O3 triples as well. The new rate law equation becomes:
rate'' = k''[NO][3[O3]]

Since the concentration of O3 is now tripled, the reaction rate will also triple. Therefore, tripling the partial pressure of O3 will result in a tripling of the reaction rate.

In summary:
- Doubling the partial pressure of NO will double the reaction rate.
- Tripling the partial pressure of O3 will triple the reaction rate.